24.50 g of Na react with H2O to make sodium hydroxide and H, gas. How much sodium hydroxide is made if there is an excess of water?

42.61 g of NaOH.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2Na + 2H₂O —> 2NaOH + H₂

Next, we shall determine the mass of Na that reacted and the mass of NaOH produced from the balanced equation. This is illustrated below:

Molar mass of Na = 23 g/mol

Mass of Na from the balanced equation = 2 × 23 = 46 g

Molar mass of NaOH = 23 + 16 + 1

= 40 g/mol

Mass of NaOH from the balanced equation = 2 × 40 = 80 g

SUMMARY:

From the balanced equation above,

46 g of Na reacted to produce 80 g of NaOH.

Finally, we shall determine the mass of NaOH produced by the reaction of 24.50 g of Na. This can be obtained as follow:

From the balanced equation above,

46 g of Na reacted to produce 80 g of NaOH.

Therefore, 24.50 g of Na will react to produce = (24.50 × 80)/46 = 42.61 g of NaOH.

Thus, 42.61 g of NaOH were obtained from the reaction.