What is the mass of solute in 0.150 L of 0.42 M glucose (C6H12O6)?

Hey there!:

Molar mass NaCl = 58.44 g/mol

number of moles:

n = M * V

n = 0.150 * 2.50

n = 0.375 moles of NaCl

Therefore:

1 mol NaCl 58.44 g

0.375 moles m

m = 0.375 * 58.44 / 1

m = 21.915 g of NaCl

hope this helps!

Explanation:

confused

confused             hewdejdnjnjsnd