Suppose you are performing a liquid-liquid extraction. First, mix water with benzoic acid and sucrose
Add diethyl ether and mix again
Move the mixture to a separatory funnel, shake it gently and open the tap to release the excess vapor pressure
Let it rest for a few minutes
Open the tap and release the organic and aqueous phase

Explain
Why two phases are formed in the ether and water mixture?
In the extraction you performed, in which solvent (water or ether) was the acid dissolved and why?​

b. acid is the correct answer @jayxboof all social media

acid : acids are those which accepts an electron-pairs.

base : bases are those which donates ab electron-pairs.

alkali : it is a base that dissolves in water. it is basically a base and the ph greater than 7.

hydroxide ion : it is a poly-atomic ion which is negatively charged.

- lead + phosphoric acid = hydrogen + lead(ii) phosphate

with this one i know the answer in craters one reason i looked it up and i learned about it there is my evidence

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2