a balloon filled with a volume of 1.50 L is compressed to a volume of 0.50 L at a constant rate of temperature. if the initial pressure of the gas inside the balloon was 1.65 atm what is the new pressure?

New pressure P2 = 4.95 atm

Explanation:

Given:

Old volume V1 = 1.50 L

New volume V2 = 0.50 L

Old pressure P1 = 1.65 atm

Find:

New pressure P2

Computation:

P1V1 = P2V2

So,

(1.50)(1.65) = (0.50)(P2)

New pressure P2 = 4.95 atm

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.