Consider the heating curve. A graph of temperature versus time, with time in minutes as the horizontal axis and temperature in degrees Celsius as the vertical axis. 5 sections of line are labeled: 1 from 0 minutes, negative 50 degrees to 1, 0 degrees. 2: from 1, 0 to 5, 0. 3: from 5, 0 to 9, 2200. 4: from 9, 2200 to 17, 2200. 5: from 17.0, 2200 to off the chart at 2,400 degrees.
In which region are most particles moving the fastest?
2
3
4
5

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.

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i believe the answer is a.