Phosphorous trichloride (PC13) is produced from the reaction of white phosphorous (P1)
and chlorine:
Pa(s) + 6 Cl2(g) → 4PC13(g)
A sample of PCl, of mass 253.7 g was collected
from the reaction of 77.97 of P, with excess
chlorine. What is the percentage yield of the
reaction?
Answer in units of %

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o