NaN3 → 2 Na + 3 N2 (2 mole ratio

Explanation:

Balanced Equation

2NaN

3

(

s

)

→

2Na(s)

+

3N

2

(

g

)

We will be doing the following pattern to answer this question.

mass N

2

→

mol N

2

→

mol NaN

3

→

mass NaN

3

We need the molar ratios between

NaN

3

and

N

2

.

From the equation, we can see that there are two mole ratios:

2

mol NaN

3

3

mol N

2

and

3

mol N

2

2

molNaN

3

We need to determine the molar masses of the nitrogen gas and sodium azide.

Molar Mass

N

2

:

(

2

×

14.0067 g/mol)=

28.0134

g/mol N

2

Molar Mass

NaN

3

:

65.009869 g/mol NaN

3

Next we need to determine how many moles are in

12.0 g N

2

by dividing Its given mass by its molar mass. We will need to do the same for

NaN

3

.

Moles

N

2

:

12.0

g N

2

×

1 mol N

2

28.0134

g N

2

=

0.4284 mol N

2

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To determine the moles of

NaN

3

, we need to multiply the mole ratio from the equation. We will need to use the mole ratio from the equation with

NaN

2

in the numerator.

0.4284

mol N

2

×

2

mol NaN

3

3

mol N

2

=

0.2856 mol NaN

3

Now we need to multiply the moles

NaN

3

by its molar mass.

0.2856

mol NaN

3

×

65.009869

g NaN

3

1

mol NaN

3

=

18.6 g NaN

3

the answer is definitely c.

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