What is the number of copper atom in one naira coin which weight is 7.3g a sum of the material is 86%

5.9x10²² atoms of Cu are in one naira coin

Explanation:

To solve this question we need to find the mass of Copper. Then, using its molar mass (Cu = 63.546g/mol) we must find the moles of Cu and its atoms using Avogadro's number:

Mass Cu:

7.3g * 86% = 6.278g is the mass of Cu.

Moles Cu:

6.278g * (1mol / 63.546g) = 0.099moles Cu

Atoms Cu:

0.099moles Cu * (6.022x10²³atoms / 1mol) =

take a better picture and ill do it

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole