Consider the following intermediate chemical equations. C(s)+1/2O2(g) -> CO(g)
CO(g)+1/2O2(g )-> CO2(g)
How will the oxygen appear in the final chemical equation?
O2(g) as a product
O2(g) as a reactant
O(g) as a product
2O(g) as a reactant

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atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of carbon is as shown here in the image.