What is the mole percent of ethanol (C2H5OH), which consists of 71.0 g of ethanol for every 18.6 g of water present?A. 87.7%.B. 22.1%.C. 26.5%.D. 73.5%.E. 71.0%.

Mole percent of Ethanol = 0.5986 * 100 = 59.86%

Explanation:

Mole percent is the percentage of the total moles that is of a particular component.

We have to covert the ethanol and water to moles. This is given by the equation;

Number of moles =  Mass / Molar mass

Ethanol;

Number of moles = 71 / 46.07  = 1.5411 mol

Water;

Number of moles = 18.6 / 18  = 1.033 mol

Total mol = 1.5411 mol + 1.033 mol =  2.5741 mol

Mole percent of Ethanol = Number of moles /(Ethanol) / Total moles   * 100

Mole percent of Ethanol =  1.5411 mol / 2.5741 mol   * 100

Mole percent of Ethanol = 0.5986 * 100 = 59.86%

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error