How many grams do 1.8 x 1020 atoms of phos- phorus weight​

9.2 x 10⁻³ grams

Explanation:

1mole P = 6.02 x 10²³ atoms

So, no. moles in 1.8 x 10²⁰ atoms P = 1.8 x 10²⁰ / 6.02 x 10²³atoms/mole = 2.99 x 10⁻⁴ mole

Grams P = moles x formula weight of P = 2.99 x 10⁻⁴ mole x 30.9738 g/mole = 9.26 x 10⁻³ grams P

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

there are no statements provided but here is why:

sulfur belongs to group 16 because it can be found in nature whether it is in a free or combined state.

hope this