For the equation SnO2 + 2H2 Sn + 2H2O, tin (IV) oxide reacts with excess hydrogen to produce tin and water. What is the limiting reactant? A) SnO2
B) H2
C) Sn
D) H2O

SnO2

Explanation:

The limiting reactant is the reactant that runs out first during a chemical reaction.

Reactants are on the left side of the reaction, so SnO2 and H2. They tell us in the question that there is "excess" hydrogen (H2), so we know there is plenty of it, as "excess" means "more than enough." If we have more than enough hydrogen, then we know that we will run out of SnO2 first.

:)

SnO2

Explanation:

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"