A balloon has a volume of 0.8.0 m3. As it rises in the earth s atmosphere, its volume expands. What will be its new volume if its original temperature and pressure are 20 C and 1.0 atm, and its final temperature and pressure are -40 C and 0.10 atm

6.36 m³

Explanation:

Using the general gas law

P₁V₁/T₁ = P₂V₂/T₂

Given that P₁ = 1.0 atm, V₁ = 0.8 m³ and T₁ = 20 °C = 273 + 20 = 293 K and P₂ = 0.10 atm, V₂ = unknown and T₂ = -40 °C = 273 + (-40) = 273 - 40 = 233 K

So, V₂ = P₁V₁T₂/P₂T₁

Substituting the values of the variables into the equation, we have

V₂ = 1.0 atm × 0.8 m³ × 233 K/0.10 atm × 293 K

V₂ = 186.4 atm-K-m³/29.3 atm-K

V₂ = 6.36 m³

So, the new volume of the balloon is 6.36 m³.

under a microscope, cancer cells may look very different from normal cells. they often have different sizes and some may be larger than normal while others are smaller. cancer cells are often abnormally shaped and the control centre of the cell (the nucleus) may have an abnormal appearance.

i think? ?