¿Cuándo se agrega la leche y té, se te forman enlaces internos entre las dos sustancias?

Given,

Mass of carbon fiber brakes = 90.7 kg = 90.7 x 1000 = 90700 g  

Mass of the rubber tires = 123 kg = 123 x 1000 = 123000

Specific heat of carbon fiber = 1.400Jg∘C

As all the heat is transferred from the carbon fiber brakes to the rubber tires, the heat lost by the carbon fiber brakes is equal to the heat gained by the rubber tires.

So the temperature change of carbon fiber brakes, delta T = 172∘C

And the temperature change of rubber tires, delta T = 172∘C

The formula used for heat is,  

Q = m s delta T

where Q is heat, m is mass, s is specific heat, and delta T is the temperature change

We know,  

Heat lost by the carbon fiber brakes = Heat gained by the rubber tires

90700 g x 1.400Jg∘C x 172∘C = 123000 g x s x 172∘C

or,  90700 g x 1.400Jg∘C = 123000 g x s

or, s =  (90700 g x 1.400Jg∘C) / 123000 g

or, s = 1.03236

Therefore, the specific heat of rubber tires is 1.03236 Jg∘C

Explanation:

yes it is balanced