what would the ph be at the end of an enzyme-catalyzed reaction if it were carried out in a 0.1 m phosphate buffer of pka 6.86 and 0.005 m of acid was produced during the reaction

Ph of the enzyme -catalyzed reaction = 6.77

Explanation:

Given data:

concentration phosphate buffer =  0.1 m

pka. = 6.86  

concentration of acid in the reaction = 0.005 m

Determine the  Ph at the end of the reaction

For a balanced buffer solution ; Acid amount = base amount

first we will determine the concentration of acid and base in relation to the buffer

acid = 0.1 / 2 = 0.05

base = 0.1 /2 = 0.05

The chemical reaction of the buffer can be expressed as attached below

PH = pka + log =

     = 6.86 + log ( 0.8181 ) = 6.77

h let me think

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