How many grams of CaCO3 are needed to react with HCl to produce 80g of calcium chloride

CaCO

3

 is the reactant in excess.

The amount of  

CaCO

3

remaining is  

11.5 g

.

Explanation:

Write a balanced equation.

CaCO

3

+

2HCl

→

CaCl

2

+

CO

2

+

H

2

O

Use the balanced equation to determine the mole ratios between  

CaCO

3

and  

CaCl

2

and between  

HCl

and  

CaCl

2

and between  

CaCO

3

and  

HCl

Calcium carbonate and calcium chloride.

1 mol CaCO

3

1 mol CaCl

2

and  

1 CaCl

2

1 mol CaCO

3

Hydrochloric acid and calcium chloride.

2 mol HCl

1 CaCl

2

and  

1 mol CaCl

2

2 HCl

Calcium carbonate and hydrochloric acid.

1 mol CaCO

3

2 mol HCl

and  

2 mol HCl

1 mol CaCO

3

Determine the moles of each reactant by dividing the given masses by their molar masses.

28.0

g CaCO

3

×

1

mol CaCO

3

100.1

g CaCO

3

=

0.280 mol CaCO

3

12.0

g HCl

×

1

mol HCl

36.5

g HCl

=

0.329 mol HCl

Determine the mass of  

CaCl

2

produced by each reactant by multiplying the moles of each reactant times the mole ratios with  

CaCl

2

in the numerator. Then multiply the result by the molar mass of  

CaCl

2

(

111 g/mol

)

.

Calcium carbonate

0.280

mol CaCO

3

×

1

mol CaCl

2

1

mol CaCO

3

×

111

g CaCl

2

1

mol CaCl

2

=

31.1 g CaCl

2

Hydrochloric acid

0.329

mol HCl

×

1

mol CaCl

2

2

mol HCl

×

111

g CaCl

2

1

mol CaCl

2

=

18.3 g CaCl

2

Since hydrochloric acid yields less calcium chloride than calcium carbonate, it is the limiting reactant .

Calcium carbonate is the excess reactant .

Determine the mass of  

CaCO

3

that reacted with the limiting reactant  

HCl

.

0.329

mol HCl

×

1

mol CaCO

3

2

mol HCl

×

100.1

g CaCO

3

1

mol CaCO

3

=

16.5 g CaCO

3

.

reacted

To determine the mass of  

CaCO

3

that remains, subtract the mass that reacted from the starting mass.

28.0 g

−

16.5 g

=

11.5 g

Explanation:

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.