The rate constant for a second order reaction is 1.70-106 M-15-1 at 900 K. The rate constant at 1200 K is 3.81.107 M-15-1. What is the activation energy for the reaction? [? ]kJ/mol Recall that R = 8.314 J/mol K Enter text here Enter​

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

if you mean hydrogen and oxygen then water is the product

with this one i know the answer in craters one reason i looked it up and i learned about it there is my evidence