Which statement is true for London dispersion forces? Question 1 options:

At any given point in time, a partial charge called an instantaneous dipole can form in a molecule, producing a repulsion between neighboring molecules.

Larger atoms require lower boiling points than smaller atoms to overcome the strong intermolecular attraction.

The attraction between induced dipole–instantaneous dipole pairs is very strong and permanent.

The strength of intermolecular attractive forces is greater in larger molecules than in smaller molecules.

i just learnt this recently but i need to look through my notes again

answer: gold foil experiment - he shot alpha particles at a gold foil

explanation:

answer is: empirical formula is tl₂o. if we use 100 grams of compound, tha:

m(tl) = 96.2%  · 100 g ÷ 100%.

m(tl) = 96.2 g.

n(tl) = m(tl)  ÷ m(tl). n(tl) = 96.2 g  ÷ 204.4 g/mol.

n(tl) = 0.47 mol. m(o) = 3.77 g. n(o) = m(o)  ÷ m(o). n(o) = 3.77 g  ÷ 16 g/mol. n(ag) = 0.235 mol. n(tl) . n(o) = 0.47 mol : 0.235 mol /0.235. n(tl) . n(o) = 2 : 1.

m(tl₂o) = 204.4 g/mol  · 2 + 16 g/mol = 424.8 g/mol.

m(compound) = 456. 8 g/mol - 424.8 g/mol = 32 g/mol ( 2 oxygens); tl₂o₃.