What is the empirical formula of a hypothetical compound that is 96%S and 4% H?​

Explanation:

Let the mass of the compound be 100g.

Mass of Sulfur = 96g.

=> Moles of Sulfur

= 96g / (32.07g/mol) ≈ 3

Mass of Hydrogen = 4g.

=> Moles of Hydrogen

= 4g / (1.008g/mol) ≈ 4

Mole ratio of Sulfur to Hydrogen = 3 : 4,

Empirical formula of compound = S3H4.

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.