5.478 grams of potassium acetate and 2.143 grams of iron(III) hydroxide are added to a beaker containing 100.0 mL of water and stirred vigorously. A solid settles to the bottom of the beaker. If the water is decanted and the solid is dried, what is the maximum mass of solid that should be recovered

Solution :

(iron          (potassium

hydroxide)     acetate)

Number of moles of

                                                = 0.02005 mol

Number of moles of

                                                = 0.0585 mol

Since 1 mol of reacts with 3 mols of

Therefore, number of moles of reacted mol

                                                                                    = 0.0195 mol

Therefore the limiting reagent is and hence the number of moles of produced is 0.0195 mol

Amount of  produced = moles x molar mass

                                                           = 0.0195 moles x 232.98 g/mol

                                                          = 4.5431 g