A 200 g block of a substance requires 520 J of heat to raise its temperature from 25°C to 45°C. Use the table to identify the substance.

The answer is gold.

Explanation:

Substance: Specific Heat (C) in joules per gram/degrees centigrade:

Water (ice) 2.05

Iron 0.46

Aluminium 0.90

Gold 0.13

Copper 0.39

Ammonia (liquid) 4.70

Ethanol 2.44

Gasoline 2.22

Water (liquid) 4.18

Water (vapor) 2.08

Air (25 degrees Celsius) 1.01

Oxygen 0.92

Hydrogen 14.30

To know that we clear the equation q=m*C*Δt for the specific heat (C) and solve the equation. Keep in mind that we need to use the heat (520 J) in Joules since the values from the question and the table are in Joules.

q/m∗ΔT = C = 520J/200g∗(45degC−25degC) =

0.13J/gdegC

As you can see, the substance that has this specific heat is GOLD.

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