91.2 g Mn
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
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Parenthesis
Exponents
Multiplication
Division
Addition
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Left to Right
Chemistry
Atomic Structure
Reading a Periodic TableAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Stoichiometry
Using Dimensional AnalysisExplanation:
Step 1: Define
[Given] 1.00 × 10²⁴ atoms Mn
Step 2: Identify Conversions
Avogadro's Numer
[PT] Molar Mass of Mn - 54.94 g/mol
Step 3: Convert
[DA] Set up:
![\displaystyle 1.00 \cdot 10^{24} \ atoms \ Mn(\frac{1 \ mol \ Mn}{6.022 \cdot 10^{23} \ atoms \ Mn})(\frac{54.94 \ g \ Mn}{1 \ mol \ Mn})](/tpl/images/1135/2989/700be.png)
[DA] Multiply/Divide [Cancel out units]:
![\displaystyle 91.2321 \ g \ Mn](/tpl/images/1135/2989/d1476.png)
Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
91.2321 g Mn ≈ 91.2 g Mn