Arrange the liquids pentane (CH3CH2CH2CH2CH3), pentanol (CH3CH2CH2CH2CH2OH), and pentanal (CH3CH2CH2CH2CHO) in order of decreasing viscosity, surface tension, and boiling point. Rank from highest to lowest viscosity, surface tension, and boiling point.

Following are decreasing order to this question:

Explanation:

Viscosity and surface tension both are inter-molecular by nature (IMFs)

The pentane becomes non-polar and just not H-bondable, so LDF alone would be likely (London Dispersion Force)

Pentanal, but H-bond => is impossible (Dipole-Dipole)

Pentanol is also an OH group, so H-bond => is probable (Hydrogen Bonding)

Higher air tension and viscosity than higher IMFs (because the atoms of fluids are more drawn). To lower the IMF (and therefore the viscosity/surface stress decreases)

pentanol

pentanal

pentane

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !