How many moles of O2, form as 80 g of KClO3 are totally consumed?
M(KCIO3)= 122.45 g/mol.

0.975 mole of O₂

Explanation:

We'll begin by calculating the number of mole in 80 g of KClO₃. This can be obtained as follow:

Molar mass of KClO₃ = 122.45 g/mol.

Mass of KClO₃ = 80 g

Mole of KClO₃ =?

Mole = mass /Molar mass

Mole of KClO₃ = 80 / 122.45

Mole of KClO₃ = 0.65 mole

Next, we shall write the balanced equation for the reaction. This is illustrated below:

2KClO₃ —> 2KCl + 3O₂

From the balanced equation above,

2 moles of KClO₃ decomposed to produce 3 moles of O₂.

Finally, we shall determine the number of mole O₂ produced by the decomposition of 80 g (i.e 0.65 mole) of KClO₃. This can be obtained as follow:

From the balanced equation above,

2 moles of KClO₃ decomposed to produce 3 moles of O₂.

Therefore, 0.65 mole of KClO₃ will decompose to produce = (0.65 × 3)/2 = 0.975 mole of O₂.

Thus, 0.975 mole of O₂ was obtained from the reaction.

a. energy is absorbed in the reaction.

if in a given reaction the energy of products is greater than the energy of reactants it means that reaction is endothermic and during the reaction, the energy is absorbed by reactants. in an endothermic reaction, the products have more stored chemical energy than the reactants. and in this reaction the reactants are more stable than products before the compounds with less energy are always more stable.

air

in a tire you fill a tire with air

then a couple days later you check the air pressure in the tire

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