If the point of the nail can be approximated as a circle with a radius 2.00×10^-3m What is the pressure in MPa exerted on the wall if a hammer strikes the nail with a force of 104 N

8.28 MPa

Explanation:

From the question given above, the following data were obtained:

Radius (r) = 2×10¯³ m

Force applied (F) = 104 N

Pressure (P) =?

Next, we shall determine the area of the nail (i.e circle). This can be obtained as follow:

Radius (r) = 2×10¯³ m

Area (A) of circle =?

Pi (π) = 3.14

A = πr²

A = 3.14 × (2×10¯³)²

A = 3.14 × 4×10¯⁶

A = 1.256×10¯⁵ m²

Next, we shall determine the pressure. This can be obtained as follow:

Force applied (F) = 104 N

Area (A) = 1.256×10¯⁵ m²

Pressure (P) =?

P = F / A

P = 104 / 1.256×10¯⁵

P = 8280254.78 Nm¯²

Finally, we shall convert 8280254.78 Nm¯² to MPa. This can be obtained as follow:

1 Nm¯² = 1×10¯⁶ MPa

Therefore,

8280254.78 Nm¯² = 8280254.78 Nm¯² × 1×10¯⁶ MPa / 1 Nm¯²

8280254.78 Nm¯² = 8.28 MPa

Thus, the pressure exerted on the wall is 8.28 MPa

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.