How many atoms are in 4.5 g of AICI3?

2.047 × 10^22 atoms.

Explanation:

To calculate the number of atoms (nA) in AlCl3, we first need to find the number of moles in the compound, AlCl3.

Molar mass of AlCl3 = 27 + 35.5(3)

= 27 + 106.5

= 133.5g/mol

Using mole = mass/molar mass

mole = 4.5/133.5

mole = 0.034moles

number of atoms in a substance (nA) = number of moles (n) × Avagadros number or constant (6.02 × 10^23 atoms)

nA of AlCl3 = 0.034 × 6.02 × 10^23

nA = 0.2047 × 10^23

nA = 2.047 × 10^22 atoms.

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