How many moles of oxygen gas are produced in the decomposition of 5.00g of potassium chlorate? Given: KClO3= O2+KCl

0.0612 moles of O2 produced

Explanation:

     First we convert from grams of Potassium Chlorate to moles..

Amu = 122.5

5.00g / 122.5 g = 0.0408163265 moles of Potassium Chlorate

    Now we need to use the chemical equation to find the ratio of Potassium Chlorate to Oxygen... But first, we need to balance it

Original Chemical Equation : KClO3 = O2 + KCl

Balanced Chemical Equation : 2KClO3 = 3O2 + 2KCl

     Now we will use the balanced chemical equation to find the ratio of Potassium Chlorate to oxygen (in order to convert to moles of oxygen for our answer)

We can see that for every 2 moles of Potassium Chlorate that are decomposing, we have 3 moles of oxygen gas produced.

So, we will set up our conversion factor like this:

0.0408163265 moles KClO3 *   3 moles Oxygen

                                                     2 moles KClO3

When we solve for this, we see that there are 0.0612244898 moles of O2 produced, or 0.0612 moles of O2 produced

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.