A. Calculate the percentage yield for SiO2 for trial 1. Also, determine the leftover reactant for the trial. Show your Work. b. Based on the percentage yield in trial 2, explain what ratio of reactants is more efficient for the given reaction.

answer carbon and three oxygen atoms;

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.