Percentage compostion of carbon in caco3

Ca = 40.08 amu
C = 12.01 amu
O = 16 * 3 = 48 amu

40.08 + 12.01 + 48 = 100.09 total amu

12.01 / 100.09 = 0.1199 * 100 = about 12% C

To find percent composition carbon you do

12.01 amu divided by the total amu of compound times 100..

amu is just the atomic mass number of the element/compound

m=9

step-by-step explanation:

7m+8=71 subtract   8 from 71 which is 63 than divide it by 7m   equal 9.

                             

The answer is 323 g.