how many grams of magnesium oxide would be produced if 3.8 grams of magnesium reacted completely with 2.1 grams of oxygen? explain your answer

Approx. a

10

⋅

g

mass is formed.

Explanation:

M

g

(

s

)

+

1

2

O

2

(

g

)

→

M

g

O

(

s

)

Moles of metal

=

6.0

⋅

g

24.31

⋅

g

⋅

m

o

l

−

1

=

0.247

⋅

m

o

l

.

And thus there are

0.247

⋅

m

o

l

×

40.3

⋅

g

⋅

m

o

l

−

1

magnesium oxide

≅

10

⋅

g

Explanation:

hope it helps can u get branliest pls

heat or electricity in the atmosphere- c.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.