Help me plsss What is the mass in grams of H₂ that can be formed from 47.2 grams of NH₃ in the following reaction?
2 NH₃(g) → 3 H₂(g) + N₂(g)

8.34

Explanation:

1) how much moles of NH₃ are in the reaction;

2) how much moles of H₂ are in the reaction;

3)  the required mass of the H₂.

all the details are in the attachment; the answer is marked with red colour.

Note1: M(NH₃) - molar mass of the NH₃, constant; M(H₂) - the molar mass of the H₂, constant; ν(NH₃) - quantity of NH₃; ν(H₂) - quantity of H₂.

Note2: the suggested solution is not the shortest one.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.