For snap How many moles of lithium hydroxide would be required to produce 67.5 g of Li₂CO₃ in the following chemical reaction?
2 LiOH(s) + CO₂(g) → Li₂CO₃(s) + H₂O(l)

Molar mass Li2CO3 = 73.89 g/mol
Mol Li2CO3 = 67.5/73.89 =0.91 mol
Mol LiOH = 1.82 mol
Mark it brainliest please?

Because electrons have negligible mass, to account for the mass of the isotope, there must be 16 neutrons, 16 neutrally charged, massive, fundamental particles present in the sulfur nucleus. and thus finally, if we have the 32s2− ion, there are 18 electrons, 16 protons, and 16 neutrons.