The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In the first step of the Ostwald process, ammonia is reacted with oxygen gas to produce nitric oxide and water. What is the maximum mass of H2O that can be produced by combining 75.9 g of each reactant? 4NH3(g)+5O2(g)⟶4NO(g)+6H2O(g)

51.1 g of H2O

Explanation:

The equation of the reaction is;

4NH3(g)+5O2(g)⟶4NO(g)+6H2O(g)

We decide on the limiting reactant;

Number of moles of NH3 = 75.9 g/17 g/mol = 4.46 moles

If 4 moles of NH3 produced 6 moles of H2O

4.46 moles of NH3 will produce 4.46 * 6/4 = 6.69 moles of H2O

For O2

Number of moles of O2 = 75.9 g/32g/mol = 2.37 moles

If 5 moles of O2 produced 6 moles of H2O

2.37 moles of O2 will produce 2.37 * 6/5 = 2.84 moles of H2O

Hence O2 is the limiting reactant

Mass of water produced = 2.84 moles of H2O * 18 g/mol = 51.1 g of H2O

answer: option (4) is the correct answer.

explanation:

areas which are at low altitudes and near the equator tend to receive direct sunlight from the sun. hence, heat energy or radiations from the sun make these areas warmer and they have warmest water.

whereas areas which are at high altitudes and away from the equator do no receive direct sunlight. hence, no direct contact from the sun makes these regions colder and thus, they have colder water.

thus, we can conclude that the statement areas at low latitudes near the equator have the warmest water because they receive the most direct sunlight best explains the relationship between an area's geography and the temperature of its surface water.