What is the approximate volume of 280 g of chlorine gas (Cl2) at STP

78 L Cl₂

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to Right

Chemistry

Atomic Structure

Reading a Periodic TableSTP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Stoichiometry

Using Dimensional AnalysisExplanation:

Step 1: Define

280 g Cl₂

Step 2: Identify Conversions

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of Cl₂ - 2(35.45) = 70.90 g/mol

[STP] 1 mol = 22.4 L

Step 3: Convert

[DA] Set up:                                                                                                   [DA] Multiply/Divide [Cancel out units]:                                                      

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

78.4981 L Cl₂ ≈ 78 L Cl₂

And a) oxygen i believe

Sorry i dont understand the question can you rephase it?