A student determines the molar mass of acetone, CH3COCH3, by the method used in this experiment. She found that the equilibrium temperature of a mixture of ice and water was 1.0 degrees C on her thermometer. When she added 11.1 g of her sample to the mixture, the temperature, after thorough stirring, fell to -3.0 degrees C. She then poured off the solution through a screen into a beaker. The mass of the solution was 90.4 g. a) What was the freezing point depression?b) What was the molality of acetone? I need help especially with this one. c) How much acetone was in the decanted solution?d) How much water is in the decanted solution?e) How much acetone would there be in a solution containing 1 kg of water and acetone at the same concentration as she had in her experiment?f) What did she find to be the molar mass of acetone, assuming she made the calculation properly?
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Consider the following reactions. (note: (s) = solid, (l) = liquid, and (g) = gas.) mg(s) + ½o2(g) → mgo(s) + 146 kcal/mole h2(g) + ½o2(g) → h2o(g), δh = -57.82 kcal/mole what type of reaction is represented by the previous two examples?
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An atom of which element reacts with an atom of hydrogen to form a bond with the greatest degree of polarity ?
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A student determines the molar mass of acetone, CH3COCH3, by the method used in this experiment. She...
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