How many moles are equal to 13.2 L of NFCI3 gas at STP? Need the equation

0.589 moles

Explanation:

1 mol of any gas at STP (Standard Temperature and Pressure) occupies 22.4 L. So, we can define the ratio: 1 mol/22.4 L.

According to that, we can multiply the volume of NFCI₃ gas by the ratio, to obtain the number of moles there is in that volume:

moles of NFCI₃ = 13.2 L x 1 mol/22.4 L = 0.589 moles

Therefore, in 13.2 L of NFCI₃ gas, there are 0.589 moles.

the answer is b. dilution