If 1.50g lead(II) nitrate is reacted with 1.75g sodium chromate what is the theoretical yield of the precipitate?

1.46g of PbCrO₄ are the theoretical yield

Explanation:

Theoretical yield is defined as the maximum amount of products that could be produced (Assuming a yield of 100%).

The reaction of Lead (II) nitrate with sodium chromate is:

Pb(NO₃)₂(aq) + Na₂CrO₄(aq) → PbCrO₄(s) + 2NaNO₃ (aq)

First, we need to find molar mass of each reactant in order to determine limiting reactant (As the reaction is 1:1, the reactant with the lower number of moles is the limiting reactant). The moles of the limiting reactant = moles of Lead (II) chromate (The precipitate):

Moles Pb(NO₃)₂ -Molar mass: 331.21g/mol-

1.50g * (1mol / 331.21g) = 4.53x10⁻³ moles Pb(NO₃)₂

Moles Na₂CrO₄ -Molar mass: 161.98g/mol-

1.75g * (1mol / 161.98g) = 0.0108 moles

Pb(NO₃)₂ is limiting reactant and moles of PbCrO₄ are 4.53x10⁻³ moles. The mass is:

4.53x10⁻³ moles PbCrO₄ * (323.19g / mol) =

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates