How many grams of CO are needed to react with an excess of Fe2O3 to produce 209.7 g Fe? Equation Fe2O2(g) + 3CO(g) -> 3CO2(g) + 2Fe(g)

157.3 g CO

Explanation:

Fe2O3  + 3CO —> 3CO2 + 2Fe [1 mol + 3 mol —> 3 mol + 2 mol]

3 mol CO —> 2 mol Fe

3*28g —> 2*56g

amt CO 3*28*209.7/(2*56) = 157.3g

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates

i think its 5049.

i hope this !