Please help find the impractical formula of the compound that contains 46.6 g of magnesium 61.4 g of sulfur and 92.0 g of oxygen. type subscripts for each element

The empirical formula is

Explanation:

Mass of Mg= 46.6 g

Mass of S= 61.4 g

Mass of O = 92.0 g

Step 1 : convert given masses into moles.

Moles of Mg =

Moles of S =

Moles of O =

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Mg =

For S=

For O =

The ratio of Mg: S: O = 1: 1: 3

Hence the empirical formula is