Students performed a procedure similar to part ii of this experiment (analyzing juices for vitamin c content) as described in the procedure section. three 10.00ml samples of juice were titrated with dcp that had a standardized concentration of 9.98x10-4m. the three titrations took an average of 16.34ml of dcp. calculate the mass (in mg) in 50.00ml of juice. (mm ascorbic acid = 176.124 g/mol)

Explanation:

Hello,

In this case, the titration is based of the equality between the moles of the titrant and the analyte, then, in terms of molarity we define it as shown below:

As the ascorbic acid is the substance reacting with the DCP, we infer that the 16.34 mL of DCP completely neutralized the ascorbic acid; in such a way, solving for the molarity of the neutralized acid, one obtains:

Finally, by using the molar MASS of the ascorbic acid and applying the proper units conversion, the result is shown below:

Therefore, 14.36 mg of ascorbic acid are contained into 50.00mL of juice.

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answer: e.   sour taste

explanation: acids are those substances which dissociates in water to give ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. acids are sour in taste. example: hcl

bases are those substances which dissociates in water to give ions or accepts ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. bases are bitter in taste. bases are slippery in nature.

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

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(jacemorris04)