KMnO4 + H2S + HCl KCl + MnCl2 + H2O + S8 Did Cl change oxidation number? Yes, no Did Oxygen change oxidation number? Yes, no Did H change oxidation number? Yes, no Did Mn change oxidation number? Yes, no Did S change oxidation number? Yes, no oxidizing agent = K, O, Mn, S reducing agent = Mn, H, Cl, S

Explanation:

KMnO4 + H2S + HCl --> KCl + MnCl2 + H2O + S8

Did Cl change oxidation number?

The oxidation  number of Cl in Reactant side is -1

The oxidation number of Cl in product side is -1

NO

Did Oxygen change oxidation number?

The oxidation number of O in Reactant side is -2

The oxidation number of O in product side is -2

NO

Did H change oxidation number?

The oxidation number of H in Reactant side is 1

The oxidation number of H in product side is 1

NO

Did Mn change oxidation number?

The oxidation number of Mn in Reactant side is +7

The oxidation number of Mn in product side is +2

YES

Did S change oxidation number?

The oxidation number of S in Reactant side is -2

The oxidation number of S in product side is 0

YES

Oxidizing agent (element with decrease in oxidation number) = Mn

Reducing agent (element with Increase in oxidation number) = S

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

what does the table look like