1.204 x 10^24 molecules of CH3COOH is how many grams?

120.1 g CH₃COOH

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Atomic Structure

Reading a Periodic TableAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional AnalysisExplanation:

Step 1: Define

1.204 × 10²⁴ molecules CH₃COOH

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of C - 12.01 g/mol

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of CH₃COOH - 12.01 + 3(1.01) + 12.01 + 16.00 + 16.00 + 1.01 = 60.06 g/mol

Step 3: Convert

Set up:                               Multiply/Divide:                                                                                                      

Step 4: Check

Follow sig fig rules and round. We are given 4 sig figs.

120.08 g CH₃COOH ≈ 120.1 g CH₃COOH

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