BRIANLIEST Use the mass to calculate the number of moles in a 347.89 g samples of ammonium

20.46 moles

Explanation:

1 mole of NH3 contains 17gm of NH3

so 347.89 gm of ammonia is in,

347.89/17 moles

=20.46 moles

NOTE. There should be ammonia instead of ammonium in question because ammonium is an ion not a compound.

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

c (diamond),

sio2 (quartz)