Problem 6.14 in book We can look at the band structure of an element to get an idea of how many electrons per atom participate in conduction. We can also determine this number based on the free electron density, the atomic mass, and the mass density of the material. (a) Calculate the free electron density of lithium. The Fermi energy is 4.72 eV. (b) Derive a formula for the number of atoms per unit volume. (c) Calculate the number of atoms per unit volume of lithium (535 kg/m3, 6.9 g/mol) using the formula you derived in part (b). (d) Determine the number of free electrons per lithium atom. (e) What is the electron configuration for Li

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Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.