Rank the following elements in INCREASING Atomic Radius: Fe, Ni, K, Ti (SMALLEST TO LARGEST)
a. Ti, Ni, Fe, K
b. Ni, Fe, Ti, K
c. Fe, Ti, K, Ni
d. K, Ti, Fe, Ni

b. Ni, Fe, Ti, K

Explanation:

The given elements are present in period 4 of periodic table. Now we will discuss the trend of atomic radius along period.

Atomic radius:

" It is the smallest distance from nucleus to the outer most valance shell of an atom"

When we move from left to right in the periodic table the number of valance electrons in an atom increase. The atomic size goes to decrease in same period because of edition of electron with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. In this way positive charge is also going to increase and this charge is greater in effect than the charge of electrons. This effect causes the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell come closer to the nucleus.

As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.

Ni ∠ Fe ∠ Ti ∠ K

on passing the small ampere of electric current through the tube made of ar and hg of cfl generates uv rays which excites the fluorescent and thus emits the high radiation by consumption of just 5- 12 w in comparison to incandescent light which requires more power such as around 40 - 55 w to lighten.

moreover the life span of fluorescent or cfl is around 8000 h whereas the life span of incandescent is around 1200 h

hence, the building installed with incandescent lights bears more electricity bill.