What is the mass of reactants in the following equation? N2 + 3H2 > 2NH3 Question 3 options: 34.05 amu 31.03 amu 30.02 amu 15.01 amu

34.06amu

Explanation:

The reaction expression is given  as:

          N₂   +   3H₂   →    2NH₃  

We are to find the mass of reactants in the equation given;

  Here:

      Mass of reactants  = 2(atomic mass of N) + 3[ 2 x atomic mass of H]

 Atomic mass of N  = 14.0067amu

 Atomic mass of H = 1.008amu

      Mass of reactants  = 2(14.0067) + 3(2 x 1.008)  = 34.06amu

not clear

some sources quote the lethal dose, for an average 170lbs opiate-naive individual is between 75 and 375 mg