The molecular mass of air, at standard pressure and temperature, is approximately 28.97 g/mol. Calculate the mass of 3.33 moles of air.
Next, cancel like terms and units. Which of the following shows the correct terms and units canceled?

The answer is B, edge 2021

The mass of air : 96.5 g air

Given

The molecular mass of air, at STP : 28.97 g/mol.

3.33 moles of air

Required

The mass

Solution

The mole is the number of particles contained in a substance

1 mol = 6.02.10²³

Moles can also be determined from the amount of substance mass and its molar mass

mol = mass : molar mass

mass = mol x molar mass

Input the value :

mass = 3.33 moles air x 28.97 g air/1 mol air

mass = 96.47 g ≈ 96.5 g air

i think it is true since you can test the answer and can use observations to complete it.