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2H2S + 3O2 --> 2H2O + 2SO2

2 mol H2S/8 mol H2O = 0.25 mol

Explanation:

Reactants: H is 2; S is 1; O is 2

Products: H is 2; S is 1; O is 3

There are 3 oxygens so add a 2 to the H2O e and 3 to the reactants side.

H2S + 3O2 → 2H2O + SO2

Reactant side: H is 2; S is 1; O is 6

Product side: H is 4; S is 1; O is 4

Hydrogen is now out of balance, so a coefficient of 2 can be placed in front of H2S to give:

2H2S + 3O2 → 2H2O + SO2

Reactant side: H is 4; S is 2; O is 6

Product side: H is 4; S is 1; O is 4

Sulfur is unbalanced, so a coefficient of 2 can be placed in front of SO2 to give:

2H2S + 3O2 → 2H2O + 2SO2

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied