The complete combustion of acetic acid, HC2H3O2(I) to form water, H2O(I), and CO2(g), at constant pressure releases 871.7 kJ of heat per mol of acetic acid. Write a balanced thermochemical equation if 5.0g of acetic acid will be used in the reaction.
HC2H3O2(I) + O2 --- H2O(I) + CO2(g) H= -871.7 kJ

HC2H3O2(I) + O2(g) ---> H2O(I) + CO2(g) ΔH= -72.35 kJ

Explanation:

We know that 5.0 g of acetic acid will contain, 5.0g/60 g/mol = 0.083 moles of acetic acid

Now from the reaction equation;

1 mole of acetic acid evolved -871.7 KJ of heat

0.083 moles of acetic acid will evolve 0.083 * -871.7 = -72.35 KJ

For 5.0 g of acetic acid, we can write;

HC2H3O2(I) + O2(g) ---> H2O(I) + CO2(g) ΔH= -72.35 kJ

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.