A 5.0 g sample of metal was heated to a temperature of 100.0 °C then placed into a calorimeter containing 35 mL of water at 20.0°C. The final temperature was 26.5°C What is the specific heat capacity of the metal?

The specific heat capacity of the metal : c = 2.59  J/g °C

Given

5 g sample

35 ml water = 35 g

Required

The specific heat capacity of the metal

Solution

Heat can be formulated :

Q = m.c.Δt

Q in = Q out

Q absorbed = Q released

Q water = Q metal

35 g x 4.184 J/g °C x (26.5-20)= 5 x c x (100-26.5)

951.86 J = 367.5 x c

c = 2.59  J/g °C

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explanation: